8. Calculate the enthalpy of the reaction P4(s) + 10Cl2(g) → 4PCl5(s) from the reactions: P4(s) + 6Cl2(g) → 4PCl3(l) △ H= -1278.8KJ PCl3(l) + Cl2(g) → PCl5(s) △ H= -124KJ
(A)1.154
(B)-1.775
(C)-1.154
(D)2.433
(E)1.503MJ‧ mol-1